Here You will know only about the subject of Electronic Device And Circuit Theory ( ELECTRONICS 1)
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Saturday, December 6, 2008
Sunday, November 9, 2008
Output Impedance of a Transistor for the Emitter Follower (Common Collector)
Zout = - dVout / dIout
The minus sign in the derivative comes from the fact the output impedance has the effect of decreasing Vout. The output current IE, which is related to the base current.
Vin = IBRS + VBE +VE [Vout = VE]
Vout = VE = Vin – IBRS – VBE [Iout = IE and IB = IE/(β + 1)]
Vout = Vin – {IE/(β + 1)}RS – VBE = Vin – {Iout/( β + 1)}RS – VBE
= - Iout{RS/(β + 1)} + (Vin – VBE)
So, Zout = - dVout/dIout = -d/dIout [ - Iout{RS/(β + 1)} + (Vin – VBE) ]
Zout = RS/(β + 1)
Thus we obtain the result that the impedance of the source, as viewed by the load, is reduced by the factor ~ 1/ β.
Zout = {RS/( β + 1) ≈ RS/β |
Saturday, November 8, 2008
Types of Amplifiers
The transistor is a three terminal device, thus the input and the output must share one terminal in collector, common emitter, and common base.